line p goes through (6,12) and has a slope of 5/2 please write in slope-intercept form

Answer:The equation of line P with slope [tex]\frac{5}{2}[/tex] and points ( 6 , 12 ) is  y = [tex]\frac{5}{2}[/tex] x - 3  .  Step-by-step explanation:Given as :The slope of the line P is [tex]\frac{5}{2}[/tex]The line P passes through point ( 6 , 12 )Now, Equation of line in slope intercept form can be written as :[tex]y-y_1 = m( x - x_1)[/tex]Or, y-12 = [tex]\frac{5}{2}[/tex] ( x - 6)Or ,  y - 12 = [tex]\frac{5}{2}[/tex] x -  [tex]\frac{5}{2}[/tex] × 6O y - 12 =  [tex]\frac{5}{2}[/tex] x - 15 Or, y = [tex]\frac{5}{2}[/tex] x - 15 + 12∴    y = [tex]\frac{5}{2}[/tex] x - 3Hence The equation of line P with slope [tex]\frac{5}{2}[/tex] and points           ( 6 , 12 ) is  y = [tex]\frac{5}{2}[/tex] x - 3  .  Answer