Please help ASAPWhat are the equations of the asymptotes of the hyperbola?(y+4)^2/36−(x−6)^2/49=1Enter your answer in point-slope form. Enter the slope as a simplified fraction.
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Answer:The answer to your question is belowStep-by-step explanation: [tex]\frac{(y + 4)^{2} }{36} + \frac{(x - 6)^{2} }{49} = 1[/tex]a² = 36 a = 6b² = 49 b = 7asymptotes y = ± [tex]\frac{b}{a} x[/tex] y = [tex]\frac{7}{6} x[/tex] 6y = 7x y = [tex]\frac{-7}{6}x[/tex] 6y = -7x