A recent study conducted by the state government attempts to determine whether the voting public supports a further increase in cigarette taxes. The opinion poll recently sampled 1,500 voting age citizens. 1,020 of the sampled citizens were in favor of an increase in cigarette taxes. The state government would like to decide if there is enough evidence to establish whether the proportion of citizens supporting an increase in cigarette taxes is significantly greater than .66. What is the alternative hypothesis?H_0:p≤1200 , H_a:p>1200H_0:p≤1500 , H_a:p>1500H_0:p≤0.66 , H_a:p>0.66H_0:μ<0.66 , H_a:P≥0.66

Answer:For this case we want to determine if  there is enough evidence to establish whether the proportion of citizens supporting an increase in cigarette taxes is significantly greater than .66 (a;ternative hypothesis) and then the system of hypothesis are:Null hypothesis: [tex] p \leq 0.66 [/tex]Alternative hypothesis: [tex] p >0.66[/tex]And the estimated proportion for this case would be:[tex] \hat p =\frac{X}{n} = \frac{1020}{1500}=0.68[/tex]Step-by-step explanation:Previous conceptsA hypothesis is defined as "a speculation or theory based on insufficient evidence that lends itself to further testing and experimentation. With further testing, a hypothesis can usually be proven true or false".   The null hypothesis is defined as "a hypothesis that says there is no statistical significance between the two variables in the hypothesis. It is the hypothesis that the researcher is trying to disprove".  The alternative hypothesis is "just the inverse, or opposite, of the null hypothesis. It is the hypothesis that researcher is trying to prove".  Solution to the problemFor this case we want to determine if  there is enough evidence to establish whether the proportion of citizens supporting an increase in cigarette taxes is significantly greater than .66 (a;ternative hypothesis) and then the system of hypothesis are:Null hypothesis: [tex] p \leq 0.66 [/tex]Alternative hypothesis: [tex] p >0.66[/tex]And the estimated proportion for this case would be:[tex] \hat p =\frac{X}{n} = \frac{1020}{1500}=0.68[/tex]